f(A) + [ f(C) - f(A) ] ⋅ [ B - A ] / [ C - A ] = f(B)

Weg 1:

Schritt 1:
f(A) + [ f(C) - f(A) ] ⋅ [ B - A ] / [ C - A ] = f(B)
h(A) + [ h(C) - h(A) ] ⋅ [ B - A ] / [ C - A ] = h(B)

Schritt 2:
f(B) + [ h(B) - f(B) ] ⋅ [ g - f ] / [ h - f ] = g(B)

Weg 2:

Schritt 1:
f(A) + [ h(A) - f(A) ] ⋅ [ g - f ] / [ h - f ] = g(A)
f(C) + [ h(C) - f(C) ] ⋅ [ g - f ] / [ h - f ] = g(C)

Schritt 2:
g(A) + [ g(C) - g(A) ] ⋅ [ B - A ] / [ C - A ] = g(B)

Kathrin Redenius
Version: 24/10/2017